Preparing NOJ

Farewell Party

1000ms 262144K

Description:

Chouti and his classmates are going to the university soon. To say goodbye to each other, the class has planned a big farewell party in which classmates, teachers and parents sang and danced.

Chouti remembered that $$$n$$$ persons took part in that party. To make the party funnier, each person wore one hat among $$$n$$$ kinds of weird hats numbered $$$1, 2, \ldots n$$$. It is possible that several persons wore hats of the same kind. Some kinds of hats can remain unclaimed by anyone.

After the party, the $$$i$$$-th person said that there were $$$a_i$$$ persons wearing a hat differing from his own.

It has been some days, so Chouti forgot all about others' hats, but he is curious about that. Let $$$b_i$$$ be the number of hat type the $$$i$$$-th person was wearing, Chouti wants you to find any possible $$$b_1, b_2, \ldots, b_n$$$ that doesn't contradict with any person's statement. Because some persons might have a poor memory, there could be no solution at all.

Input:

The first line contains a single integer $$$n$$$ ($$$1 \le n \le 10^5$$$), the number of persons in the party.

The second line contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$0 \le a_i \le n-1$$$), the statements of people.

Output:

If there is no solution, print a single line "Impossible".

Otherwise, print "Possible" and then $$$n$$$ integers $$$b_1, b_2, \ldots, b_n$$$ ($$$1 \le b_i \le n$$$).

If there are multiple answers, print any of them.

Sample Input:

3
0 0 0

Sample Output:

Possible
1 1 1

Sample Input:

5
3 3 2 2 2

Sample Output:

Possible
1 1 2 2 2

Sample Input:

4
0 1 2 3

Sample Output:

Impossible

Note:

In the answer to the first example, all hats are the same, so every person will say that there were no persons wearing a hat different from kind $$$1$$$.

In the answer to the second example, the first and the second person wore the hat with type $$$1$$$ and all other wore a hat of type $$$2$$$.

So the first two persons will say there were three persons with hats differing from their own. Similarly, three last persons will say there were two persons wearing a hat different from their own.

In the third example, it can be shown that no solution exists.

In the first and the second example, other possible configurations are possible.

Info

CodeForces

Provider CodeForces

Origin Avito Cool Challenge 2018

Code CF1081B

Tags

constructive algorithmsimplementation

Submitted 23

Passed 13

AC Rate 56.52%

Date 03/04/2019 16:43:12

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