Preparing NOJ

Splitting into digits

1000ms 262144K


Vasya has his favourite number $$$n$$$. He wants to split it to some non-zero digits. It means, that he wants to choose some digits $$$d_1, d_2, \ldots, d_k$$$, such that $$$1 \leq d_i \leq 9$$$ for all $$$i$$$ and $$$d_1 + d_2 + \ldots + d_k = n$$$.

Vasya likes beauty in everything, so he wants to find any solution with the minimal possible number of different digits among $$$d_1, d_2, \ldots, d_k$$$. Help him!


The first line contains a single integer $$$n$$$ — the number that Vasya wants to split ($$$1 \leq n \leq 1000$$$).


In the first line print one integer $$$k$$$ — the number of digits in the partition. Note that $$$k$$$ must satisfy the inequality $$$1 \leq k \leq n$$$. In the next line print $$$k$$$ digits $$$d_1, d_2, \ldots, d_k$$$ separated by spaces. All digits must satisfy the inequalities $$$1 \leq d_i \leq 9$$$.

You should find a partition of $$$n$$$ in which the number of different digits among $$$d_1, d_2, \ldots, d_k$$$ will be minimal possible among all partitions of $$$n$$$ into non-zero digits. Among such partitions, it is allowed to find any. It is guaranteed that there exists at least one partition of the number $$$n$$$ into digits.

Sample Input:


Sample Output:

 1 1 

Sample Input:


Sample Output:

 2 2 2 

Sample Input:


Sample Output:

 3 9 9 9 


In the first test, the number $$$1$$$ can be divided into $$$1$$$ digit equal to $$$1$$$.

In the second test, there are $$$3$$$ partitions of the number $$$4$$$ into digits in which the number of different digits is $$$1$$$. This partitions are $$$[1, 1, 1, 1]$$$, $$$[2, 2]$$$ and $$$[4]$$$. Any of these partitions can be found. And, for example, dividing the number $$$4$$$ to the digits $$$[1, 1, 2]$$$ isn't an answer, because it has $$$2$$$ different digits, that isn't the minimum possible number.



Provider CodeForces

Origin Codeforces Round #534 (Div. 2)

Code CF1104A


constructive algorithmsimplementationmath

Submitted 22

Passed 18

AC Rate 81.82%

Date 03/04/2019 16:49:27


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