Preparing NOJ

# A+B Problem

1000ms 65536K

## Description:

Given two integers $a$ and $b$, calculate their sum.

## Input:

Two integers $a$ and $b$, satisfying $-32767 \le a, b \le 32767$.

## Output:

An integer, denotes the sum of $a$ and $b$.

## Sample Input:

1 2

## Sample Output:

3

## Note:

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use scanf in C or cin in C++ to read from stdin, and use printf in C or cout in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a Wrong Answer.

User programs are not allowed to open and read from/write to files. You will get a Runtime Error or a Wrong Answer if you try to do so.

Here is a sample solution using C++/G++ :

#include <iostream>

using namespace std;

int main()
{
int a,b;
cin >> a >> b;
cout << a+b << endl;
return 0;
}


It's important that the return type of main() must be int when you use G++/GCC, or you may get compile error.

Here is a sample solution using C/GCC :

#include <stdio.h>

int main()
{
int a,b;
scanf("%d %d",&a, &b);
printf("%d\n",a+b);
return 0;
}


Here is a sample solution using Java :

import java.io.*;
import java.util.*;
public class Main
{
public static void main(String args[]) throws Exception
{
Scanner cin=new Scanner(System.in);
int a=cin.nextInt(),b=cin.nextInt();
System.out.println(a+b);
}
}


With one of the most elegant languages in the world, PHP could do that within one line :

<?=array_sum(fscanf(STDIN, "%d %d"));


Here is a sample solution using Python2

print sum(int(x) for x in raw_input().split(' '))


Here is a sample solution using Python3

print(sum(int(x) for x in input().split(' ')))


Here is a sample solution using Go

package main
import "fmt"
func main() {
var a, b int
fmt.Scanf("%d%d", &a, &b)
fmt.Printf("%d\n", a + b)
}


Here is a sample solution using C#

using System;
using System.Linq;

class Program {
public static void Main(string[] args) {
}
}


Here is a sample solution using Javascript

const [a, b] = readline().split(' ').map(n => parseInt(n, 10));
print((a + b).toString());


Here is a sample solution using Ruby

a, b = gets.split.map(&:to_i)
puts(a + b)


Here is a sample solution using Rust

use std::io;

fn main() {
let mut line = String::new();

let sum: i32 = line.split_whitespace()
.map(|x| x.parse::<i32>().expect("integer"))
.sum();
println!("{}", sum);
}


Here is a sample solution using Haskell

main = print . sum . map read . words =<< getLine


Here is a sample solution using Free Pascal

var a, b:longint;
begin
writeln(a + b);
end.


Here is a sample solution using Free Basic

Dim a As Integer
Dim b As Integer

Open Cons For Input As #1
Input #1, a, b
Print Str(a+b)


Here is a sample solution using Wenyan, of which you may ask, why I am seeing this?

施「require('fs').readFileSync」於「「/dev/stdin」」。名之曰「數據」。



Here is a sample solution using Text :

WAAAAAAAIT A MINUTE, THERE IS NONE! STOP DAYDREAMING.

Info

Provider NOJ

Code NOJ1001

Tags

Submitted 2751

Passed 1311

AC Rate 47.66%

Date 08/20/2021 19:49:10

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